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9m^2-27m+14=0
a = 9; b = -27; c = +14;
Δ = b2-4ac
Δ = -272-4·9·14
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-15}{2*9}=\frac{12}{18} =2/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+15}{2*9}=\frac{42}{18} =2+1/3 $
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